3/4s+5=17

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Solution for 3/4s+5=17 equation: 



3/4s+5=17

We move all terms to the left:

3/4s+5-(17)=0



Domain of the equation: 4s!=0

s!=0/4

s!=0

s∈R



We add all the numbers together, and all the variables

3/4s-12=0

We multiply all the terms by the denominator


-12*4s+3=0

Wy multiply elements

-48s+3=0

We move all terms containing s to the left, all other terms to the right

-48s=-3

s=-3/-48

s=1/16

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