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3/4p-4/5=2/3p
We move all terms to the left:
3/4p-4/5-(2/3p)=0
Domain of the equation: 4p!=0
p!=0/4
p!=0
p∈R
Domain of the equation: 3p)!=0We add all the numbers together, and all the variables
p!=0/1
p!=0
p∈R
3/4p-(+2/3p)-4/5=0
We get rid of parentheses
3/4p-2/3p-4/5=0
We calculate fractions
(-144p^2)/300p^2+225p/300p^2+(-200p)/300p^2=0
We multiply all the terms by the denominator
(-144p^2)+225p+(-200p)=0
We get rid of parentheses
-144p^2+225p-200p=0
We add all the numbers together, and all the variables
-144p^2+25p=0
a = -144; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·(-144)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*-144}=\frac{-50}{-288} =25/144 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*-144}=\frac{0}{-288} =0 $
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