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3/4n+5=2/3n
We move all terms to the left:
3/4n+5-(2/3n)=0
Domain of the equation: 4n!=0
n!=0/4
n!=0
n∈R
Domain of the equation: 3n)!=0We add all the numbers together, and all the variables
n!=0/1
n!=0
n∈R
3/4n-(+2/3n)+5=0
We get rid of parentheses
3/4n-2/3n+5=0
We calculate fractions
9n/12n^2+(-8n)/12n^2+5=0
We multiply all the terms by the denominator
9n+(-8n)+5*12n^2=0
Wy multiply elements
60n^2+9n+(-8n)=0
We get rid of parentheses
60n^2+9n-8n=0
We add all the numbers together, and all the variables
60n^2+n=0
a = 60; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·60·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*60}=\frac{-2}{120} =-1/60 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*60}=\frac{0}{120} =0 $
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