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3/4m-5/8m=6
We move all terms to the left:
3/4m-5/8m-(6)=0
Domain of the equation: 4m!=0
m!=0/4
m!=0
m∈R
Domain of the equation: 8m!=0We calculate fractions
m!=0/8
m!=0
m∈R
24m/32m^2+(-20m)/32m^2-6=0
We multiply all the terms by the denominator
24m+(-20m)-6*32m^2=0
Wy multiply elements
-192m^2+24m+(-20m)=0
We get rid of parentheses
-192m^2+24m-20m=0
We add all the numbers together, and all the variables
-192m^2+4m=0
a = -192; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-192)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-192}=\frac{-8}{-384} =1/48 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-192}=\frac{0}{-384} =0 $
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