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3/4m-2/5m=-7
We move all terms to the left:
3/4m-2/5m-(-7)=0
Domain of the equation: 4m!=0
m!=0/4
m!=0
m∈R
Domain of the equation: 5m!=0We add all the numbers together, and all the variables
m!=0/5
m!=0
m∈R
3/4m-2/5m+7=0
We calculate fractions
15m/20m^2+(-8m)/20m^2+7=0
We multiply all the terms by the denominator
15m+(-8m)+7*20m^2=0
Wy multiply elements
140m^2+15m+(-8m)=0
We get rid of parentheses
140m^2+15m-8m=0
We add all the numbers together, and all the variables
140m^2+7m=0
a = 140; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·140·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*140}=\frac{-14}{280} =-1/20 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*140}=\frac{0}{280} =0 $
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