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3/4m-10=-1/2m-4
We move all terms to the left:
3/4m-10-(-1/2m-4)=0
Domain of the equation: 4m!=0
m!=0/4
m!=0
m∈R
Domain of the equation: 2m-4)!=0We get rid of parentheses
m∈R
3/4m+1/2m+4-10=0
We calculate fractions
6m/8m^2+4m/8m^2+4-10=0
We add all the numbers together, and all the variables
6m/8m^2+4m/8m^2-6=0
We multiply all the terms by the denominator
6m+4m-6*8m^2=0
We add all the numbers together, and all the variables
10m-6*8m^2=0
Wy multiply elements
-48m^2+10m=0
a = -48; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-48)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-48}=\frac{-20}{-96} =5/24 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-48}=\frac{0}{-96} =0 $
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