3/4m+5=m

Solution for 3/4m+5=m equation:

3/4m+5=m

We move all terms to the left:

3/4m+5-(m)=0


Domain of the equation: 4m!=0

m!=0/4

m!=0

m∈R


We add all the numbers together, and all the variables

-1m+3/4m+5=0

We multiply all the terms by the denominator


-1m*4m+5*4m+3=0

Wy multiply elements

-4m^2+20m+3=0

a = -4; b = 20; c = +3;
Δ = b2-4ac
Δ = 202-4·(-4)·3
Δ = 448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{448}=\sqrt{64*7}=\sqrt{64}*\sqrt{7}=8\sqrt{7}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-8\sqrt{7}}{2*-4}=\frac{-20-8\sqrt{7}}{-8}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+8\sqrt{7}}{2*-4}=\frac{-20+8\sqrt{7}}{-8}
$