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3/4g=12g
We move all terms to the left:
3/4g-(12g)=0
Domain of the equation: 4g!=0We add all the numbers together, and all the variables
g!=0/4
g!=0
g∈R
-12g+3/4g=0
We multiply all the terms by the denominator
-12g*4g+3=0
Wy multiply elements
-48g^2+3=0
a = -48; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-48)·3
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*-48}=\frac{-24}{-96} =1/4 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*-48}=\frac{24}{-96} =-1/4 $
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