3/4g-9=g=1)

Solution for 3/4g-9=g=1) equation:

3/4g-9=g=1)

We move all terms to the left:

3/4g-9-(g)=0


Domain of the equation: 4g!=0

g!=0/4

g!=0

g∈R


We add all the numbers together, and all the variables

-1g+3/4g-9=0

We multiply all the terms by the denominator


-1g*4g-9*4g+3=0

Wy multiply elements

-4g^2-36g+3=0

a = -4; b = -36; c = +3;
Δ = b2-4ac
Δ = -362-4·(-4)·3
Δ = 1344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1344}=\sqrt{64*21}=\sqrt{64}*\sqrt{21}=8\sqrt{21}$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-8\sqrt{21}}{2*-4}=\frac{36-8\sqrt{21}}{-8}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+8\sqrt{21}}{2*-4}=\frac{36+8\sqrt{21}}{-8}
$