3/4c+5=17

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Solution for 3/4c+5=17 equation: 



3/4c+5=17

We move all terms to the left:

3/4c+5-(17)=0



Domain of the equation: 4c!=0

c!=0/4

c!=0

c∈R



We add all the numbers together, and all the variables

3/4c-12=0

We multiply all the terms by the denominator


-12*4c+3=0

Wy multiply elements

-48c+3=0

We move all terms containing c to the left, all other terms to the right

-48c=-3

c=-3/-48

c=1/16

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