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3/4a+6=5/8a
We move all terms to the left:
3/4a+6-(5/8a)=0
Domain of the equation: 4a!=0
a!=0/4
a!=0
a∈R
Domain of the equation: 8a)!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
3/4a-(+5/8a)+6=0
We get rid of parentheses
3/4a-5/8a+6=0
We calculate fractions
24a/32a^2+(-20a)/32a^2+6=0
We multiply all the terms by the denominator
24a+(-20a)+6*32a^2=0
Wy multiply elements
192a^2+24a+(-20a)=0
We get rid of parentheses
192a^2+24a-20a=0
We add all the numbers together, and all the variables
192a^2+4a=0
a = 192; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·192·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*192}=\frac{-8}{384} =-1/48 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*192}=\frac{0}{384} =0 $
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