3/4=12/y

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Solution for 3/4=12/y equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

3/4 = 12/y // - 12/y

3/4-(12/y) = 0

3/4-12*y^-1 = 0

-12*y^-1 = -3/4 // : -12

y^-1 = 1/16

-1 < 0

1/(y^1) = 1/16 // * y^1

1 = 1/16*y^1 // : 1/16

16 = y^1

y = 16

y = 16

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