3/4+(1/3)x=6

Solution for 3/4+(1/3)x=6 equation:

3/4+(1/3)x=6

We move all terms to the left:

3/4+(1/3)x-(6)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


determiningTheFunctionDomain
(1/3)x-6+3/4=0

We add all the numbers together, and all the variables

(+1/3)x-6+3/4=0

We multiply parentheses

x^2-6+3/4=0

We multiply all the terms by the denominator


x^2*4+3-6*4=0

We add all the numbers together, and all the variables

x^2*4-21=0

Wy multiply elements

4x^2-21=0

a = 4; b = 0; c = -21;
Δ = b2-4ac
Δ = 02-4·4·(-21)
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{21}}{2*4}=\frac{0-4\sqrt{21}}{8}
=-\frac{4\sqrt{21}}{8}
=-\frac{\sqrt{21}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{21}}{2*4}=\frac{0+4\sqrt{21}}{8}
=\frac{4\sqrt{21}}{8}
=\frac{\sqrt{21}}{2}
$