3/4*(-5x-8)=-6(x+4)+1/4x

Solution for 3/4*(-5x-8)=-6(x+4)+1/4x equation:

3/4(-5x-8)=-6(x+4)+1/4x

We move all terms to the left:

3/4(-5x-8)-(-6(x+4)+1/4x)=0


Domain of the equation: 4(-5x-8)!=0

x∈R



Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R


We calculate fractions


12x/(-128x^2-20x)+(-(-6x+4x0)/(-128x^2-20x)=0


We calculate terms in parentheses: +(-(-6x+4x0)/(-128x^2-20x), so:

-(-6x+4x0)/(-128x^2-20x

We add all the numbers together, and all the variables

-(-2x)/(-128x^2-20x

We multiply all the terms by the denominator


-(-2x)

We get rid of parentheses

2x

Back to the equation:

+(2x)


We multiply all the terms by the denominator


2x*(-128x^2-20x)+12x=0

We multiply parentheses

-256x^3-40x^2+12x=0

We do not support expression: x^3