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3/4(z-5)=-12
We move all terms to the left:
3/4(z-5)-(-12)=0
Domain of the equation: 4(z-5)!=0We add all the numbers together, and all the variables
z∈R
3/4(z-5)+12=0
We multiply all the terms by the denominator
12*4(z-5)+3=0
Wy multiply elements
48z(z+3=0
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