3/4(z+20)=2+1/2(z-2)

Solution for 3/4(z+20)=2+1/2(z-2) equation:

3/4(z+20)=2+1/2(z-2)

We move all terms to the left:

3/4(z+20)-(2+1/2(z-2))=0


Domain of the equation: 4(z+20)!=0

z∈R



Domain of the equation: 2(z-2))!=0

z∈R


We calculate fractions


(6zz/(4(z+20)*2(z-2)))+(-4zz/(4(z+20)*2(z-2)))=0


We calculate terms in parentheses: +(6zz/(4(z+20)*2(z-2))), so:

6zz/(4(z+20)*2(z-2))

We multiply all the terms by the denominator


6zz

Back to the equation:

+(6zz)



We calculate terms in parentheses: +(-4zz/(4(z+20)*2(z-2))), so:

-4zz/(4(z+20)*2(z-2))

We multiply all the terms by the denominator


-4zz

Back to the equation:

+(-4zz)


We get rid of parentheses

6zz-4zz=0