3/4(y-4)+2=y-4

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Solution for 3/4(y-4)+2=y-4 equation: 



3/4(y-4)+2=y-4

We move all terms to the left:

3/4(y-4)+2-(y-4)=0



Domain of the equation: 4(y-4)!=0

y∈R



We get rid of parentheses

3/4(y-4)-y+4+2=0

We multiply all the terms by the denominator


-y*4(y-4)+4*4(y-4)+2*4(y-4)+3=0

Wy multiply elements

-4y^2(y+16y(y+8y(y+3=0

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