3/4(x-7)=-1/4(2x+5)

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Solution for 3/4(x-7)=-1/4(2x+5) equation: 



3/4(x-7)=-1/4(2x+5)

We move all terms to the left:

3/4(x-7)-(-1/4(2x+5))=0



Domain of the equation: 4(x-7)!=0

x∈R





Domain of the equation: 4(2x+5))!=0

x∈R



We calculate fractions


(12x2/(4(x-7)*4(2x+5)))+(-(-4xx)/(4(x-7)*4(2x+5)))=0



We calculate terms in parentheses: +(12x2/(4(x-7)*4(2x+5))), so:

12x2/(4(x-7)*4(2x+5))

We multiply all the terms by the denominator


12x2

We add all the numbers together, and all the variables

12x^2

Back to the equation:

+(12x^2)





We calculate terms in parentheses: +(-(-4xx)/(4(x-7)*4(2x+5))), so:

-(-4xx)/(4(x-7)*4(2x+5))

We multiply all the terms by the denominator


-(-4xx)

We get rid of parentheses

4xx

Back to the equation:

+(4xx)

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