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3/4(x-3)-5=1/8(x-1)
We move all terms to the left:
3/4(x-3)-5-(1/8(x-1))=0
Domain of the equation: 4(x-3)!=0
x∈R
Domain of the equation: 8(x-1))!=0We calculate fractions
x∈R
(24xx/(4(x-3)*8(x-1)))+(-4xx/(4(x-3)*8(x-1)))-5=0
We calculate terms in parentheses: +(24xx/(4(x-3)*8(x-1))), so:
24xx/(4(x-3)*8(x-1))
We multiply all the terms by the denominator
24xx
Back to the equation:
+(24xx)
We calculate terms in parentheses: +(-4xx/(4(x-3)*8(x-1))), so:We get rid of parentheses
-4xx/(4(x-3)*8(x-1))
We multiply all the terms by the denominator
-4xx
Back to the equation:
+(-4xx)
24xx-4xx-5=0
We move all terms containing x to the left, all other terms to the right
24xx-4xx=5
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