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3/4(x-1)=1/5(2x-1)
We move all terms to the left:
3/4(x-1)-(1/5(2x-1))=0
Domain of the equation: 4(x-1)!=0
x∈R
Domain of the equation: 5(2x-1))!=0We calculate fractions
x∈R
(15x2/(4(x-1)*5(2x-1)))+(-4xx/(4(x-1)*5(2x-1)))=0
We calculate terms in parentheses: +(15x2/(4(x-1)*5(2x-1))), so:
15x2/(4(x-1)*5(2x-1))
We multiply all the terms by the denominator
15x2
We add all the numbers together, and all the variables
15x^2
Back to the equation:
+(15x^2)
We calculate terms in parentheses: +(-4xx/(4(x-1)*5(2x-1))), so:We get rid of parentheses
-4xx/(4(x-1)*5(2x-1))
We multiply all the terms by the denominator
-4xx
Back to the equation:
+(-4xx)
15x^2-4xx=0
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