3/4(x+3)-1/8(3x+2)=1/2x

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Solution for 3/4(x+3)-1/8(3x+2)=1/2x equation: 



3/4(x+3)-1/8(3x+2)=1/2x

We move all terms to the left:

3/4(x+3)-1/8(3x+2)-(1/2x)=0



Domain of the equation: 4(x+3)!=0

x∈R





Domain of the equation: 8(3x+2)!=0

x∈R





Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3/4(x+3)-1/8(3x+2)-(+1/2x)=0

We get rid of parentheses

3/4(x+3)-1/8(3x+2)-1/2x=0

We calculate fractions


(48x^23/(4(x+3)*8(3x+2)*2x)+(-8x^2x/(4(x+3)*8(3x+2)*2x)+(-32x^2x/(4(x+3)*8(3x+2)*2x)=0



We calculate terms in parentheses: +(48x^23/(4(x+3)*8(3x+2)*2x)+(-8x^2x/(4(x+3)*8(3x+2)*2x)+(-32x^2x/(4(x+3)*8(3x+2)*2x), so:

48x^23/(4(x+3)*8(3x+2)*2x)+(-8x^2x/(4(x+3)*8(3x+2)*2x)+(-32x^2x/(4(x+3)*8(3x+2)*2x

We do not support expression: x^23

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