3/4(x+1)-3x=1/4(2x-1)

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Solution for 3/4(x+1)-3x=1/4(2x-1) equation:



3/4(x+1)-3x=1/4(2x-1)
We move all terms to the left:
3/4(x+1)-3x-(1/4(2x-1))=0
Domain of the equation: 4(x+1)!=0
x∈R
Domain of the equation: 4(2x-1))!=0
x∈R
We add all the numbers together, and all the variables
-3x+3/4(x+1)-(1/4(2x-1))=0
We calculate fractions
-3x+(12x2/(4(x+1)*4(2x-1)))+(-4xx/(4(x+1)*4(2x-1)))=0
We calculate terms in parentheses: +(12x2/(4(x+1)*4(2x-1))), so:
12x2/(4(x+1)*4(2x-1))
We multiply all the terms by the denominator
12x2
We add all the numbers together, and all the variables
12x^2
Back to the equation:
+(12x^2)
We calculate terms in parentheses: +(-4xx/(4(x+1)*4(2x-1))), so:
-4xx/(4(x+1)*4(2x-1))
We multiply all the terms by the denominator
-4xx
Back to the equation:
+(-4xx)
determiningTheFunctionDomain 12x^2-3x+(-4xx)=0
We get rid of parentheses
12x^2-3x-4xx=0

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