3/4(u-3)=1/3(2u-5)

Solution for 3/4(u-3)=1/3(2u-5) equation:

3/4(u-3)=1/3(2u-5)

We move all terms to the left:

3/4(u-3)-(1/3(2u-5))=0


Domain of the equation: 4(u-3)!=0

u∈R



Domain of the equation: 3(2u-5))!=0

u∈R


We calculate fractions


(9u2/(4(u-3)*3(2u-5)))+(-4uu/(4(u-3)*3(2u-5)))=0


We calculate terms in parentheses: +(9u2/(4(u-3)*3(2u-5))), so:

9u2/(4(u-3)*3(2u-5))

We multiply all the terms by the denominator


9u2

We add all the numbers together, and all the variables

9u^2

Back to the equation:

+(9u^2)



We calculate terms in parentheses: +(-4uu/(4(u-3)*3(2u-5))), so:

-4uu/(4(u-3)*3(2u-5))

We multiply all the terms by the denominator


-4uu

Back to the equation:

+(-4uu)


We get rid of parentheses

9u^2-4uu=0