3/4(t-20)=12

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Solution for 3/4(t-20)=12 equation: 



3/4(t-20)=12

We move all terms to the left:

3/4(t-20)-(12)=0



Domain of the equation: 4(t-20)!=0

t∈R



We multiply all the terms by the denominator


-12*4(t-20)+3=0

Wy multiply elements

-48t(t+3=0

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