3/4(t-12)=7

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Solution for 3/4(t-12)=7 equation: 



3/4(t-12)=7

We move all terms to the left:

3/4(t-12)-(7)=0



Domain of the equation: 4(t-12)!=0

t∈R



We multiply all the terms by the denominator


-7*4(t-12)+3=0

Wy multiply elements

-28t(t+3=0

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