3/4(r+3)-1/8(3r+2)=1/2r

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Solution for 3/4(r+3)-1/8(3r+2)=1/2r equation: 



3/4(r+3)-1/8(3r+2)=1/2r

We move all terms to the left:

3/4(r+3)-1/8(3r+2)-(1/2r)=0



Domain of the equation: 4(r+3)!=0

r∈R





Domain of the equation: 8(3r+2)!=0

r∈R





Domain of the equation: 2r)!=0

r!=0/1

r!=0

r∈R



We add all the numbers together, and all the variables

3/4(r+3)-1/8(3r+2)-(+1/2r)=0

We get rid of parentheses

3/4(r+3)-1/8(3r+2)-1/2r=0

We calculate fractions


(48r^23/(4(r+3)*8(3r+2)*2r)+(-8r^2r/(4(r+3)*8(3r+2)*2r)+(-32r^2r/(4(r+3)*8(3r+2)*2r)=0



We calculate terms in parentheses: +(48r^23/(4(r+3)*8(3r+2)*2r)+(-8r^2r/(4(r+3)*8(3r+2)*2r)+(-32r^2r/(4(r+3)*8(3r+2)*2r), so:

48r^23/(4(r+3)*8(3r+2)*2r)+(-8r^2r/(4(r+3)*8(3r+2)*2r)+(-32r^2r/(4(r+3)*8(3r+2)*2r

We do not support erpression: r^23

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