3/4(b-2)=b/2

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Solution for 3/4(b-2)=b/2 equation: 


b in (-oo:+oo)

(3/4)*(b-2) = b/2 // - b/2

(3/4)*(b-2)-(b/2) = 0

3/4*(b-2)-b/2 = 0

(3/4*2*(b-2))/2-b/2 = 0

3/4*2*(b-2)-b = 0

1/2*b-3 = 0

(1/2*b-3)/2 = 0

(1/2*b-3)/2 = 0 // * 2

1/2*b-3 = 0

1/2*b-3 = 0 // + 3

1/2*b = 3 // : 1/2

b = 3/1/2

b = 6

b = 6

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