3/4(8x-4)=7x-5x+6

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Solution for 3/4(8x-4)=7x-5x+6 equation: 



3/4(8x-4)=7x-5x+6

We move all terms to the left:

3/4(8x-4)-(7x-5x+6)=0



Domain of the equation: 4(8x-4)!=0

x∈R



We add all the numbers together, and all the variables

3/4(8x-4)-(2x+6)=0

We get rid of parentheses

3/4(8x-4)-2x-6=0

We multiply all the terms by the denominator


-2x*4(8x-4)-6*4(8x-4)+3=0

Wy multiply elements

-8x^2(8-24x(8+3=0

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