3/4(8x+4)-x=1/4(12x-16)

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Solution for 3/4(8x+4)-x=1/4(12x-16) equation: 



3/4(8x+4)-x=1/4(12x-16)

We move all terms to the left:

3/4(8x+4)-x-(1/4(12x-16))=0



Domain of the equation: 4(8x+4)!=0

x∈R





Domain of the equation: 4(12x-16))!=0

x∈R



We add all the numbers together, and all the variables

-1x+3/4(8x+4)-(1/4(12x-16))=0

We calculate fractions


-1x+(12x1/(4(8x+4)*4(12x-16)))+(-4x8/(4(8x+4)*4(12x-16)))=0



We calculate terms in parentheses: +(12x1/(4(8x+4)*4(12x-16))), so:

12x1/(4(8x+4)*4(12x-16))

We multiply all the terms by the denominator


12x1

We add all the numbers together, and all the variables

12x

Back to the equation:

+(12x)





We calculate terms in parentheses: +(-4x8/(4(8x+4)*4(12x-16))), so:

-4x8/(4(8x+4)*4(12x-16))

We multiply all the terms by the denominator


-4x8

We add all the numbers together, and all the variables

-4x^8

We do not support expression: x^8

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