3/4(8c-16)=2c+12

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Solution for 3/4(8c-16)=2c+12 equation: 



3/4(8c-16)=2c+12

We move all terms to the left:

3/4(8c-16)-(2c+12)=0



Domain of the equation: 4(8c-16)!=0

c∈R



We get rid of parentheses

3/4(8c-16)-2c-12=0

We multiply all the terms by the denominator


-2c*4(8c-16)-12*4(8c-16)+3=0

Wy multiply elements

-8c^2(8-48c(8+3=0

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