3/4(4x-4)-(9+3x)2

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Solution for 3/4(4x-4)-(9+3x)2 equation: 


x in (-oo:+oo)

(3/4)*(4*x-4)-(3*x+9)^2 = 0

3/4*(4*x-4)-1*(3*x+9)^2 = 0

3/4*(4*x-4)-1*(3*x+9)^2 = 0

-9*x^2-51*x-84 = 0

-9*x^2-51*x-84 = 0

-3*(3*x^2+17*x+28) = 0

3*x^2+17*x+28 = 0

DELTA = 17^2-(3*4*28)

DELTA = -47

DELTA < 0

-3 = 0

-3 = 0

x belongs to the empty set

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