3/4(4x-1)-3x=5/4-(x+2)

Solution for 3/4(4x-1)-3x=5/4-(x+2) equation:

3/4(4x-1)-3x=5/4-(x+2)

We move all terms to the left:

3/4(4x-1)-3x-(5/4-(x+2))=0


Domain of the equation: 4(4x-1)!=0

x∈R



Domain of the equation: 4-(x+2))!=0

We move all terms containing x to the left, all other terms to the right

-(x+2))!=-4

x∈R


We add all the numbers together, and all the variables

-3x+3/4(4x-1)-(5/4-(x+2))=0

We calculate fractions


-3x+(-(x+2))+3*4)/(64x-(x+2))-16)+(-20x4/(64x-(x+2))-16)=0


We calculate terms in parentheses: +(-(x+2)), so:

-(x+2)

We get rid of parentheses

-x-2

We add all the numbers together, and all the variables

-1x-2

Back to the equation:

+(-1x-2)


We get rid of parentheses

-3x-1x+3*4)/(64x-(x+2))-16)+(-20x4/(64x-x-2-2))-16=0

We multiply all the terms by the denominator


-3x*(64x-1x*(64x+3*4)-(x+2))-20x4-x*(64x-2*(64x-2)-16)*(64x-16)+(=0

We add all the numbers together, and all the variables

-3x*(64x-1x*(64x+12)-(x+2))-20x4-x*(64x-2*(64x-2)-16)*(64x-16)+(=0

We add all the numbers together, and all the variables

-20x^4-3x*(64x-1x*(64x+12)-(x+2))-x*(64x-2*(64x-2)-16)*(64x-16)=0

We do not support expression: x^4