3/4(4x+8)=1/3(6x-12)

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Solution for 3/4(4x+8)=1/3(6x-12) equation: 



3/4(4x+8)=1/3(6x-12)

We move all terms to the left:

3/4(4x+8)-(1/3(6x-12))=0



Domain of the equation: 4(4x+8)!=0

x∈R





Domain of the equation: 3(6x-12))!=0

x∈R



We calculate fractions


(9x6/(4(4x+8)*3(6x-12)))+(-4x4/(4(4x+8)*3(6x-12)))=0



We calculate terms in parentheses: +(9x6/(4(4x+8)*3(6x-12))), so:

9x6/(4(4x+8)*3(6x-12))

We multiply all the terms by the denominator


9x6

We add all the numbers together, and all the variables

9x^6

We do not support expression: x^6

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