3/4(48-16x)=4(9-3x)

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Solution for 3/4(48-16x)=4(9-3x) equation: 



3/4(48-16x)=4(9-3x)

We move all terms to the left:

3/4(48-16x)-(4(9-3x))=0



Domain of the equation: 4(48-16x)!=0

x∈R



We add all the numbers together, and all the variables

3/4(-16x+48)-(4(-3x+9))=0

We multiply all the terms by the denominator


-((4(-3x+9)))*4(-16x+48)+3=0



We calculate terms in parentheses: -((4(-3x+9)))*4(-16x+48), so:

(4(-3x+9)))*4(-16x+48

We add all the numbers together, and all the variables

-16x+(4(-3x+9)))*4(+48

Back to the equation:

-(-16x+(4(-3x+9)))*4(+48)



We add all the numbers together, and all the variables

-(-16x+(4(-3x+9)))*448+3=0

We move all terms containing x to the left, all other terms to the right

-(-16x+(4(-3x+9)))*448=-3

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