3/4(2x-5)=(5/3x)-4

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Solution for 3/4(2x-5)=(5/3x)-4 equation: 



3/4(2x-5)=(5/3x)-4

We move all terms to the left:

3/4(2x-5)-((5/3x)-4)=0



Domain of the equation: 4(2x-5)!=0

x∈R





Domain of the equation: 3x)-4)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3/4(2x-5)-((+5/3x)-4)=0

We calculate fractions


9x/(-60x^2+8x)+(-((+5*4(2x-5))/(-60x^2+8x)=0



We calculate terms in parentheses: +(-((+5*4(2x-5))/(-60x^2+8x), so:

-((+5*4(2x-5))/(-60x^2+8x

We multiply all the terms by the denominator


-((+5*4(2x-5))



We calculate terms in parentheses: -((+5*4(2x-5)), so:

(+5*4(2x-5)



We calculate terms in parentheses: +(+5*4(2x-5), so:

+5*4(2x-5

determiningTheFunctionDomain
5*4(2x-5

Wy multiply elements

20x(2

Back to the equation:

+(20x(2)



Back to the equation:

-((20x2)



Back to the equation:

+(-(20x2)



We multiply all the terms by the denominator


((-20x2)*(-60x^2+8x)+9x=0

We add all the numbers together, and all the variables

((-20x^2)*(-60x^2+8x)+9x=0

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