3/4(2x-4)=4x+8

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Solution for 3/4(2x-4)=4x+8 equation: 



3/4(2x-4)=4x+8

We move all terms to the left:

3/4(2x-4)-(4x+8)=0



Domain of the equation: 4(2x-4)!=0

x∈R



We get rid of parentheses

3/4(2x-4)-4x-8=0

We multiply all the terms by the denominator


-4x*4(2x-4)-8*4(2x-4)+3=0

Wy multiply elements

-16x^2(2-32x(2+3=0

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