3/4(2x+4)+2(x+3)=23

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Solution for 3/4(2x+4)+2(x+3)=23 equation: 



3/4(2x+4)+2(x+3)=23

We move all terms to the left:

3/4(2x+4)+2(x+3)-(23)=0



Domain of the equation: 4(2x+4)!=0

x∈R



We multiply parentheses

3/4(2x+4)+2x+6-23=0

We multiply all the terms by the denominator


2x*4(2x+4)+6*4(2x+4)-23*4(2x+4)+3=0

Wy multiply elements

8x^2(2+24x(2-92x(2+3=0

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