3/4(2x+1)=2/3(x+1)

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Solution for 3/4(2x+1)=2/3(x+1) equation:



3/4(2x+1)=2/3(x+1)
We move all terms to the left:
3/4(2x+1)-(2/3(x+1))=0
Domain of the equation: 4(2x+1)!=0
x∈R
Domain of the equation: 3(x+1))!=0
x∈R
We calculate fractions
(9xx/(4(2x+1)*3(x+1)))+(-8x2/(4(2x+1)*3(x+1)))=0
We calculate terms in parentheses: +(9xx/(4(2x+1)*3(x+1))), so:
9xx/(4(2x+1)*3(x+1))
We multiply all the terms by the denominator
9xx
Back to the equation:
+(9xx)
We calculate terms in parentheses: +(-8x2/(4(2x+1)*3(x+1))), so:
-8x2/(4(2x+1)*3(x+1))
We multiply all the terms by the denominator
-8x2
We add all the numbers together, and all the variables
-8x^2
Back to the equation:
+(-8x^2)
We get rid of parentheses
-8x^2+9xx=0

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