3/4(2m-5)=2(3m-4)-5/6m

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Solution for 3/4(2m-5)=2(3m-4)-5/6m equation: 



3/4(2m-5)=2(3m-4)-5/6m

We move all terms to the left:

3/4(2m-5)-(2(3m-4)-5/6m)=0



Domain of the equation: 4(2m-5)!=0

m∈R





Domain of the equation: 6m)!=0

m!=0/1

m!=0

m∈R



We calculate fractions


18m/(-120m^2+8m)+(-(6m-20m2)/(-120m^2+8m)=0



We calculate terms in parentheses: +(-(6m-20m2)/(-120m^2+8m), so:

-(6m-20m2)/(-120m^2+8m

We add all the numbers together, and all the variables

-(+6m-20m^2)/(-120m^2+8m

We multiply all the terms by the denominator


-(+6m-20m^2)

We get rid of parentheses

20m^2-6m

Back to the equation:

+(20m^2-6m)



We get rid of parentheses

18m/(-120m^2+8m)+20m^2-6m=0

We multiply all the terms by the denominator


20m^2*(-120m^2+8m)-6m*(-120m^2+8m)+18m=0

We multiply parentheses

20m^2*(-120m^2+8m)+720m^3-48m^2+18m=0

We do not support empression: m^3

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