3/4(2m-5)=2(3m-4)-4/5m

Solution for 3/4(2m-5)=2(3m-4)-4/5m equation:

3/4(2m-5)=2(3m-4)-4/5m

We move all terms to the left:

3/4(2m-5)-(2(3m-4)-4/5m)=0


Domain of the equation: 4(2m-5)!=0

m∈R



Domain of the equation: 5m)!=0

m!=0/1

m!=0

m∈R


We calculate fractions


15m/(-100m^2+8m)+(-(6m-16m2)/(-100m^2+8m)=0


We calculate terms in parentheses: +(-(6m-16m2)/(-100m^2+8m), so:

-(6m-16m2)/(-100m^2+8m

We add all the numbers together, and all the variables

-(+6m-16m^2)/(-100m^2+8m

We multiply all the terms by the denominator


-(+6m-16m^2)

We get rid of parentheses

16m^2-6m

Back to the equation:

+(16m^2-6m)


We get rid of parentheses

15m/(-100m^2+8m)+16m^2-6m=0

We multiply all the terms by the denominator


16m^2*(-100m^2+8m)-6m*(-100m^2+8m)+15m=0

We multiply parentheses

16m^2*(-100m^2+8m)+600m^3-48m^2+15m=0

We do not support empression: m^3