3/4(2m-5)=2(3-4)-5/6m

Solution for 3/4(2m-5)=2(3-4)-5/6m equation:

3/4(2m-5)=2(3-4)-5/6m

We move all terms to the left:

3/4(2m-5)-(2(3-4)-5/6m)=0


Domain of the equation: 4(2m-5)!=0

m∈R



Domain of the equation: 6m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

3/4(2m-5)-(2(-1)-5/6m)=0

We calculate fractions


18m/(-120m^2+8m)+(-(-20m2)/(-120m^2+8m)=0


We calculate terms in parentheses: +(-(-20m2)/(-120m^2+8m), so:

-(-20m2)/(-120m^2+8m

We add all the numbers together, and all the variables

-(-20m^2)/(-120m^2+8m

We multiply all the terms by the denominator


-(-20m^2)

We get rid of parentheses

20m^2

Back to the equation:

+(20m^2)


We add all the numbers together, and all the variables

20m^2+18m/(-120m^2+8m)=0

We multiply all the terms by the denominator


20m^2*(-120m^2+8m)+18m=0