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3/4(2a-6)+1/6=2/5(3a+20)
We move all terms to the left:
3/4(2a-6)+1/6-(2/5(3a+20))=0
Domain of the equation: 4(2a-6)!=0
a∈R
Domain of the equation: 5(3a+20))!=0We calculate fractions
a∈R
(90a3/(4(2a-6)*5(3a+20))*6)+(-(2*4(2a-6)*6)/(4(2a-6)*5(3a+20))*6)+(20a^22/(4(2a-6)*5(3a+20))*6)=0
We calculate terms in parentheses: +(90a3/(4(2a-6)*5(3a+20))*6), so:
90a3/(4(2a-6)*5(3a+20))*6
We multiply all the terms by the denominator
90a3
We add all the numbers together, and all the variables
90a^3
We do not support eapression: a^3
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