3/4(2a-6)+1/2=2/5(a+20)

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Solution for 3/4(2a-6)+1/2=2/5(a+20) equation: 



3/4(2a-6)+1/2=2/5(a+20)

We move all terms to the left:

3/4(2a-6)+1/2-(2/5(a+20))=0



Domain of the equation: 4(2a-6)!=0

a∈R





Domain of the equation: 5(a+20))!=0

a∈R



We calculate fractions


(30aa/(4(2a-6)*5(a+20))*2)+(-(2*4(2a-6)*2)/(4(2a-6)*5(a+20))*2)+(20a^22/(4(2a-6)*5(a+20))*2)=0



We calculate terms in parentheses: +(30aa/(4(2a-6)*5(a+20))*2), so:

30aa/(4(2a-6)*5(a+20))*2

We multiply all the terms by the denominator


30aa

Back to the equation:

+(30aa)





We calculate terms in parentheses: +(-(2*4(2a-6)*2)/(4(2a-6)*5(a+20))*2), so:

-(2*4(2a-6)*2)/(4(2a-6)*5(a+20))*2

We multiply all the terms by the denominator


-(2*4(2a-6)*2)



We calculate terms in parentheses: -(2*4(2a-6)*2), so:

2*4(2a-6)*2

Wy multiply elements

16a(2

Back to the equation:

-(16a(2)



Back to the equation:

+(-(16a2)





We calculate terms in parentheses: +(20a^22/(4(2a-6)*5(a+20))*2), so:

20a^22/(4(2a-6)*5(a+20))*2

We do not support eapression: a^22

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