3/4(24-8c)=2(5c+1)

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Solution for 3/4(24-8c)=2(5c+1) equation: 



3/4(24-8c)=2(5c+1)

We move all terms to the left:

3/4(24-8c)-(2(5c+1))=0



Domain of the equation: 4(24-8c)!=0

c∈R



We add all the numbers together, and all the variables

3/4(-8c+24)-(2(5c+1))=0

We multiply all the terms by the denominator


-((2(5c+1)))*4(-8c+24)+3=0



We calculate terms in parentheses: -((2(5c+1)))*4(-8c+24), so:

(2(5c+1)))*4(-8c+24

We add all the numbers together, and all the variables

-8c+(2(5c+1)))*4(+24

Back to the equation:

-(-8c+(2(5c+1)))*4(+24)



We add all the numbers together, and all the variables

-(-8c+(2(5c+1)))*424+3=0

We move all terms containing c to the left, all other terms to the right

-(-8c+(2(5c+1)))*424=-3

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