3/4(192+x)=300

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Solution for 3/4(192+x)=300 equation: 



3/4(192+x)=300

We move all terms to the left:

3/4(192+x)-(300)=0



Domain of the equation: 4(192+x)!=0

x∈R



We add all the numbers together, and all the variables

3/4(x+192)-300=0

We multiply all the terms by the denominator


-300*4(x+192)+3=0

Wy multiply elements

-1200x(x+3=0

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