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3/4(12r-9)+r/4=5-3(2-3r)
We move all terms to the left:
3/4(12r-9)+r/4-(5-3(2-3r))=0
Domain of the equation: 4(12r-9)!=0We add all the numbers together, and all the variables
r∈R
3/4(12r-9)+r/4-(5-3(-3r+2))=0
We calculate fractions
-(5-3(-3r+2))=0
We calculate terms in parentheses: -(5-3(-3r+2)), so:We get rid of parentheses
5-3(-3r+2)
determiningTheFunctionDomain -3(-3r+2)+5
We multiply parentheses
9r-6+5
We add all the numbers together, and all the variables
9r-1
Back to the equation:
-(9r-1)
-9r+1=0
We move all terms containing r to the left, all other terms to the right
-9r=-1
r=-1/-9
r=1/9
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