3/4(12-16k)=21

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Solution for 3/4(12-16k)=21 equation: 



3/4(12-16k)=21

We move all terms to the left:

3/4(12-16k)-(21)=0



Domain of the equation: 4(12-16k)!=0

k∈R



We add all the numbers together, and all the variables

3/4(-16k+12)-21=0

We multiply all the terms by the denominator


-21*4(-16k+12)+3=0

Wy multiply elements

-84k(-+3=0

We use the square of the difference formula

-84k(-3=0

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