3/4(-8z+24)=1/2(-12z+36)

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Solution for 3/4(-8z+24)=1/2(-12z+36) equation: 



3/4(-8z+24)=1/2(-12z+36)

We move all terms to the left:

3/4(-8z+24)-(1/2(-12z+36))=0



Domain of the equation: 4(-8z+24)!=0

z∈R





Domain of the equation: 2(-12z+36))!=0

z∈R



We calculate fractions


(6z(-)/(4(-8z+24)*2(-12z+36)))+(-4z0/(4(-8z+24)*2(-12z+36)))=0



We calculate terms in parentheses: +(6z(-)/(4(-8z+24)*2(-12z+36))), so:

6z(-)/(4(-8z+24)*2(-12z+36))

We add all the numbers together, and all the variables

6z0/(4(-8z+24)*2(-12z+36))

We multiply all the terms by the denominator


6z0

We add all the numbers together, and all the variables

6z

Back to the equation:

+(6z)





We calculate terms in parentheses: +(-4z0/(4(-8z+24)*2(-12z+36))), so:

-4z0/(4(-8z+24)*2(-12z+36))

We multiply all the terms by the denominator


-4z0

We add all the numbers together, and all the variables

-4z

Back to the equation:

+(-4z)



We get rid of parentheses

6z-4z=0

We add all the numbers together, and all the variables

2z=0

z=0/2

z=0

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