3/3x-6=7/x+2

Solution for 3/3x-6=7/x+2 equation:

3/3x-6=7/x+2

We move all terms to the left:

3/3x-6-(7/x+2)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: x+2)!=0

x∈R


We get rid of parentheses

3/3x-7/x-2-6=0

We calculate fractions


3x/3x^2+(-21x)/3x^2-2-6=0

We add all the numbers together, and all the variables

3x/3x^2+(-21x)/3x^2-8=0

We multiply all the terms by the denominator


3x+(-21x)-8*3x^2=0

Wy multiply elements

-24x^2+3x+(-21x)=0

We get rid of parentheses

-24x^2+3x-21x=0

We add all the numbers together, and all the variables

-24x^2-18x=0

a = -24; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·(-24)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*-24}=\frac{0}{-48}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*-24}=\frac{36}{-48}
=-3/4
$