3/3x+7/4x=88

Solution for 3/3x+7/4x=88 equation:

3/3x+7/4x=88

We move all terms to the left:

3/3x+7/4x-(88)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We calculate fractions


12x/12x^2+21x/12x^2-88=0

We multiply all the terms by the denominator


12x+21x-88*12x^2=0

We add all the numbers together, and all the variables

33x-88*12x^2=0

Wy multiply elements

-1056x^2+33x=0

a = -1056; b = 33; c = 0;
Δ = b2-4ac
Δ = 332-4·(-1056)·0
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-33}{2*-1056}=\frac{-66}{-2112}
=1/32
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+33}{2*-1056}=\frac{0}{-2112}
=0
$